Problem 40 Methanol can be prepared from ca... [FREE SOLUTION] (2024)

Open in App

Log In Start studying!

Open in App Log out

Chapter 13: Problem 40

Methanol can be prepared from carbon monoxide and hydrogen at high temperatureand pressure in the presence of a suitable catalyst. (a) Write the expression for the equilibrium constant \(\left(K_{c}\right)\) forthe reversible reaction \(2 \mathrm{H}_{2}(g)+\mathrm{CO}(g) \rightleftharpoons\mathrm{CH}_{3} \mathrm{OH}(g) \quad \Delta H=-90.2 \mathrm{kJ}\) (b) What will happen to the concentrations of \(\mathrm{H}_{2}, \mathrm{CO},\)and \(\mathrm{CH}_{3} \mathrm{OH}\) at equilibrium if more \(\mathrm{H}_{2}\) isadded? (c) What will happen to the concentrations of \(\mathrm{H}_{2}, \mathrm{CO},\)and \(\mathrm{CH}_{3} \mathrm{OH}\) at equilibrium if CO is removed? (d) What will happen to the concentrations of \(\mathrm{H}_{2}, \mathrm{CO},\)and \(\mathrm{CH}_{3} \mathrm{OH}\) at equilibrium if \(\mathrm{CH}_{3}\mathrm{OH}\) is added? (e) What will happen to the concentrations of \(\mathrm{H}_{2}, \mathrm{CO},\)and \(\mathrm{CH}_{3} \mathrm{OH}\) at equilibrium if the temperature of thesystem is increased?

Short Answer

Expert verified

The equilibrium constant expression is \(K_c = \frac{[CH_3OH]}{[H_2]^2[CO]}\). Adding \(H_2\) or removing CO will shift the equilibrium towards more \(CH_3OH\), adding \(CH_3OH\) will shift the equilibrium towards more \(H_2\) and \(CO\), and increasing temperature will shift the equilibrium towards more \(H_2\) and \(CO\) due to the exothermic nature of the forward reaction.

Step by step solution

01

Writing the Expression for the Equilibrium Constant \(K_c\)

To write the expression for the equilibrium constant \(K_c\) of the reaction, take the concentrations of the products raised to their stoichiometric coefficients and divide by the concentrations of the reactants raised to their stoichiometric coefficients. For the reaction \(2 H_2(g) + CO(g) \rightleftharpoons CH_3OH(g)\), the expression is \[K_c = \frac{[CH_3OH]}{[H_2]^2[CO]}\].

02

Effect on Equilibrium with Increased \(H_2\)

According to Le Chatelier's Principle, increasing the concentration of \(H_2\) shifts the equilibrium to the right, favoring the production of \(CH_3OH\) and increasing its concentration, while decreasing the concentrations of \(H_2\) and \(CO\) as they are consumed.

03

Effect on Equilibrium with CO Removed

Removing CO from the system shifts the equilibrium to the left, to replace the removed CO. This decreases the concentration of \(CH_3OH\) while increasing the concentrations of \(H_2\) and \(CO\) as they are produced due to the reverse reaction.

04

Effect on Equilibrium with Added \(CH_3OH\)

Adding \(CH_3OH\) to the system shifts the equilibrium to the left, favoring the reverse reaction. The concentrations of \(H_2\) and \(CO\) increase as they are produced, and the concentration of \(CH_3OH\) will initially increase but then decrease as it is consumed.

05

Effect on Equilibrium with Increased Temperature

Since the forward reaction is exothermic (\(\Delta H=-90.2\ kJ/mole\)), increasing the temperature will shift the equilibrium to the left, as predicted by Le Chatelier's Principle. This will increase the concentrations of \(H_2\) and \(CO\), and decrease the concentration of \(CH_3OH\).

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Le Chatelier's Principle

Le Chatelier's Principle is a fundamental concept in chemistry that helps predict the effect of changing conditions on a chemical equilibrium. When a system at equilibrium is disturbed by a change in temperature, pressure, volume, or concentration, the system will adjust to counteract the change and re-establish equilibrium.

For example, increasing the concentration of reactants or decreasing the concentration of products will typically shift the equilibrium towards the product side, as the system attempts to use up the added reactants or replenish the removed products. Conversely, increasing the concentration of products or removing reactants shifts the equilibrium towards the reactants to offset the disturbance.

This principle is vividly illustrated in the production of methanol where modifications to reactant and product concentrations cause shifts in the equilibrium position to re-balance the system. Understanding how to apply Le Chatelier's Principle is essential for controlling chemical reactions in industrial processes and laboratory settings.

Equilibrium Constant

The equilibrium constant, represented by the symbol \(K_c\), is a ratio that reflects the concentrations of products and reactants at chemical equilibrium. The expression for \(K_c\) is based on a balanced chemical equation and is calculated by dividing the product of the concentrations of the products, each raised to the power of its coefficient, by the product of the concentrations of the reactants, similarly raised. The value of \(K_c\) is constant at a given temperature for a reversible reaction.

\[K_c = \frac{\text{[Products]}^{\text{coefficients}}}{\text{[Reactants]}^{\text{coefficients}}}\]
It's important to note that \(K_c\) does not involve solids or pure liquids as their concentrations do not change. In the methanol synthesis example, an increase in the value of \(K_c\) indicates a reaction favoring methanol production, while a decrease suggests a shift towards the reactants. This helps predict which way the equilibrium will shift under different conditions, which is essential for optimizing chemical processes.

Reaction Quotient

The reaction quotient, denoted \(Q_c\), serves as a predictive tool for the direction of a reaction's shift towards equilibrium. It is calculated using the same formula as the equilibrium constant \(K_c\), but with the initial concentrations of the reactants and products rather than their equilibrium concentrations.

\[Q_c = \frac{\text{[Products]}^{\text{coefficients}}}{\text{[Reactants]}^{\text{coefficients}}}\]
By comparing \(Q_c\) to \(K_c\), one can determine the reaction's direction. If \(Q_c < K_c\), the reaction will proceed forward to produce more products. If \(Q_c > K_c\), the reaction will go in the reverse direction to generate more reactants. When \(Q_c = K_c\), the system is at equilibrium. This quantitative analysis, in light of Le Chatelier's Principle, empowers students and chemists to predict and control the outcomes of reactions.

Exothermic Reactions

Exothermic reactions are chemical processes that release energy, usually in the form of heat, to the surroundings. These reactions are characterized by having negative enthalpy changes \(\Delta H\), indicating that the energy of the products is lower than the energy of the reactants. In the context of equilibrium, the concept of exothermicity has significant implications.

According to Le Chatelier's Principle, an increase in temperature for an exothermic reaction will result in a shift of the equilibrium towards the reactants to absorb the added heat. Consequently, for the methanol-producing reaction shown in the exercise, a temperature increase will cause a decrease in methanol concentration as the equilibrium adjusts in favor of the reverse reaction.

This relationship between temperature and equilibrium is crucial in industrial applications where controlling the amount of produced substances is vital. Chemical engineers must carefully manage temperatures to optimize yields in exothermic processes like methanol production.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Problem 40 Methanol can be prepared from ca... [FREE SOLUTION] (3)

Most popular questions from this chapter

Write the mathematical expression for the reaction quotient, \(Q_{c}\), for eachof the following reactions: (a) \(\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2\mathrm{NH}_{3}(g)\) (b) \(4 \mathrm{NH}_{3}(g)+5 \mathrm{O}_{2}(g) \rightleftharpoons 4\mathrm{NO}(g)+6 \mathrm{H}_{2} \mathrm{O}(g)\) (c) \(\mathrm{N}_{2} \mathrm{O}_{4}(g)=2 \mathrm{NO}_{2}(g)\) (d) \(\mathrm{CO}_{2}(g)+\mathrm{H}_{2}(g) \rightleftharpoons\mathrm{CO}(g)+\mathrm{H}_{2} \mathrm{O}(g)\) (e) \(\mathrm{NH}_{4} \mathrm{Cl}(s)=\mathrm{NH}_{3}(g)+\mathrm{HCl}(g)\) (f) \(2 \mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(s) \rightleftharpoons 2\mathrm{PbO}(s)+4 \mathrm{NO}_{2}(g)+\mathrm{O}_{2}(g)\) (g) \(2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)=2 \mathrm{H}_{2} \mathrm{O}(l)\) (h) \(S_{8}(g) \rightleftharpoons 8 S(g)\)Nitrogen and oxygen react at high temperatures. (a) Write the expression for the equilibrium constant \(\left(K_{c}\right)\) forthe reversible reaction \(\mathrm{N}_{2}(g)+\mathrm{O}_{2}(g)\rightleftharpoons 2 \mathrm{NO}(g) \quad \Delta H=181 \mathrm{kJ}\) (b) What will happen to the concentrations of \(\mathrm{N}_{2},\mathrm{O}_{2},\) and \(\mathrm{NO}\) at equilibrium if more \(\mathrm{O}_{2}\) isadded? (c) What will happen to the concentrations of \(\mathrm{N}_{2},\mathrm{O}_{2},\) and \(\mathrm{NO}\) at equilibrium if \(\mathrm{N}_{2}\) isremoved? (d) What will happen to the concentrations of \(\mathrm{N}_{2},\mathrm{O}_{2},\) and NO at equilibrium if NO is added? (e) What will happen to the concentrations of \(\mathrm{N}_{2},\mathrm{O}_{2},\) and \(\mathrm{NO}\) at equilibrium if the volume of thereaction vessel is decreased? (f) What will happen to the concentrations of \(\mathrm{N}_{2},\mathrm{O}_{2},\) and \(\mathrm{NO}\) at equilibrium if the temperature of thesystem is increased?A 0.72-mol sample of PCl_ is put into a 1.00-L vessel and heated. Atequilibrium, the vessel contains 0.40 mol of \(\mathrm{PCl}_{3}(g)\) and \(0.40\mathrm{mol}\) of \(\mathrm{Cl}_{2}(g) .\) Calculate the value of the equilibriumconstant for the decomposition of \(\mathrm{PCl}_{5}\) to \(\mathrm{PCl}_{3}\) and\(\mathrm{Cl}_{2}\) at this temperature.Show that the complete chemical equation, the total ionic equation, and thenet ionic equation for the reaction represented by the equation \(\mathrm{KI}(aq)+\mathrm{I}_{2}(a q) \rightleftharpoons \mathrm{KI}_{3}(a q)\) give the sameexpression for the reaction quotient. \(\mathrm{KI}_{3}\) is composed of theions \(K^{+}\) and \(I_{3}^{-}\)Analysis of the gases in a sealed reaction vessel containing \(\mathrm{NH}_{3},\mathrm{N}_{2},\) and \(\mathrm{H}_{2}\) at equilibrium at \(400^{\circ}\mathrm{C}\) established the concentration of \(\mathrm{N}_{2}\) to be \(1.2\mathrm{M}\) and the concentration of \(\mathrm{H}_{2}\) to be \(0.24 \mathrm{M}\). \(\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g)\quad K_{c}=0.50\) at \(400^{\circ} \mathrm{C}\) Calculate the equilibrium molar concentration of \(\mathrm{NH}_{3}\)
See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

Making Measurements

Read Explanation

Chemical Analysis

Read Explanation

Nuclear Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free

This website uses cookies to improve your experience. We'll assume you're ok with this, but you can opt-out if you wish. Accept

Privacy & Cookies Policy

Privacy Overview

This website uses cookies to improve your experience while you navigate through the website. Out of these, the cookies that are categorized as necessary are stored on your browser as they are essential for the working of basic functionalities of the website. We also use third-party cookies that help us analyze and understand how you use this website. These cookies will be stored in your browser only with your consent. You also have the option to opt-out of these cookies. But opting out of some of these cookies may affect your browsing experience.

Necessary

Always Enabled

Necessary cookies are absolutely essential for the website to function properly. This category only includes cookies that ensures basic functionalities and security features of the website. These cookies do not store any personal information.

Non-necessary

Any cookies that may not be particularly necessary for the website to function and is used specifically to collect user personal data via analytics, ads, other embedded contents are termed as non-necessary cookies. It is mandatory to procure user consent prior to running these cookies on your website.

Problem 40 Methanol can be prepared from ca... [FREE SOLUTION] (2024)
Top Articles
Latest Posts
Article information

Author: Kareem Mueller DO

Last Updated:

Views: 6059

Rating: 4.6 / 5 (46 voted)

Reviews: 93% of readers found this page helpful

Author information

Name: Kareem Mueller DO

Birthday: 1997-01-04

Address: Apt. 156 12935 Runolfsdottir Mission, Greenfort, MN 74384-6749

Phone: +16704982844747

Job: Corporate Administration Planner

Hobby: Mountain biking, Jewelry making, Stone skipping, Lacemaking, Knife making, Scrapbooking, Letterboxing

Introduction: My name is Kareem Mueller DO, I am a vivacious, super, thoughtful, excited, handsome, beautiful, combative person who loves writing and wants to share my knowledge and understanding with you.